2x^2+20xy+50y^2=0

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Solution for 2x^2+20xy+50y^2=0 equation:


Simplifying
2x2 + 20xy + 50y2 = 0

Reorder the terms:
20xy + 2x2 + 50y2 = 0

Solving
20xy + 2x2 + 50y2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(10xy + x2 + 25y2) = 0

Factor a trinomial.
2((x + 5y)(x + 5y)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(x + 5y)' equal to zero and attempt to solve: Simplifying x + 5y = 0 Solving x + 5y = 0 Move all terms containing x to the left, all other terms to the right. Add '-5y' to each side of the equation. x + 5y + -5y = 0 + -5y Combine like terms: 5y + -5y = 0 x + 0 = 0 + -5y x = 0 + -5y Remove the zero: x = -5y Simplifying x = -5y

Subproblem 2

Set the factor '(x + 5y)' equal to zero and attempt to solve: Simplifying x + 5y = 0 Solving x + 5y = 0 Move all terms containing x to the left, all other terms to the right. Add '-5y' to each side of the equation. x + 5y + -5y = 0 + -5y Combine like terms: 5y + -5y = 0 x + 0 = 0 + -5y x = 0 + -5y Remove the zero: x = -5y Simplifying x = -5y

Solution

x = {-5y, -5y}

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